1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VIII
Physics
Static Friction
If √2 =1.4142...
Question
If √2 =1.4142,then find the value of ✓√2-1÷√2+1.
Open in App
Solution
=root{[root2 + 1]/[root2 - 1] =root{[root2 + 1] [root2 + 1]/[root2 - 1][ root2 +1]} =root{[root2 + 1]^2 / (root2)^2 - 1^2} =root { [root 2 +1]^2 / 2-1} =root{[root2 +1]^2} =root2 +1 =1.414+1 =2.414//
Suggest Corrections
0
Similar questions
Q.
If
√
2
=1.4142, then find the value of
√
2
−
1
√
2
+
1
Q.
If
√
2
=
1.4142
,
t
h
e
n
√
√
2
−
1
√
2
+
1
is equal to
Q.
If
√
2
=
1.4142
then
√
√
2
−
1
√
2
+
1
=
?
Q.
If
√
2
=
1.4142
...... then
√
√
2
−
1
√
2
+
1
is equal to:
Q.
If
2
=
1
.
4142
then
2
-
1
2
+
1
is equal to
(a) 0.1718
(b) 5.8282
(c) 0.4142
(d) 2.4142