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Question
If 20ml of 0.4 N NaOH solution completely neutralise 40ml of a dibasic acid, the molarity of the acid solution is:
If 20ml of 0.4 N NaOH solution completely neutralise 40ml of a dibasic acid, the molarity of the acid solution is:
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Solution
The correct option is A 0.1M
For neutralization, no. of equivalent should be same,
N1V1=N2V2
0.4×20=N2×40
N2=0.4×2040
N2=0.2N
n-factor of acid =2→ Because of dibasic acid[2 acidic-hydrogen]
M2=N22
M2=0.22=0.1M
For neutralization, no. of equivalent should be same,
N1V1=N2V2
0.4×20=N2×40
N2=0.4×2040
N2=0.2N
n-factor of acid =2→ Because of dibasic acid[2 acidic-hydrogen]
M2=N22
M2=0.22=0.1M
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