Question 61 If 2A7 - A - 33- then find the value of A-

A × 33=2A7 We observe that A × 3 nbsp; can never be a single digit number 2, so A × 3 must be a two digit number, whose ten's digit is 2 and unit's digit is t ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Letters for Digits

Question 61 I...

Question

Question 61

If 2A7 $\div$ A = 33, then find the value of A.

Open in App

Solution

A $\times$ 33=2A7
We observe that A $\times$ 3 can never be a single digit number 2, so
A $\times$ 3 must be a two-digit number, whose ten's digit is 2 and unit's digit is the number less than or equal to A,
Therefore, the value of A can be 9, as the values of A from 1 to 8 do not fit.

Suggest Corrections

Similar questions

Question 61

If 2A7 $\div$ A = 33, then find the value of A.

Q. If 2A7

\div

A = 33, then find the value of A.

Q. If

\frac{x^{3} + 3 x}{3 x^{2} + 1} = \frac{189}{61}

then find the value of

x

Question 72

If 148101B095 is divisible by 33, find the value of B.

Q. If

33!

is divisible by

2^{n}

, then find the maximum value of n.

Join BYJU'S Learning Program

Explore more

Letters for Digits

Standard VIII Mathematics

Join BYJU'S Learning Program

Question 61 If 2A7 ÷ A = 33, then find the value of A.

A × 33=2A7 We observe that A × 3 can never be a single digit number 2, so A × 3 must be a two-digit number, whose ten's digit is 2 and unit's digit is the number less than or equal to A, Therefore, the value of A can be 9, as the values of A from 1 to 8 do not fit.

Question 61

If 2A7 $\div$ A = 33, then find the value of A.

A $\times$ 33=2A7
We observe that A $\times$ 3 can never be a single digit number 2, so
A $\times$ 3 must be a two-digit number, whose ten's digit is 2 and unit's digit is the number less than or equal to A,
Therefore, the value of A can be 9, as the values of A from 1 to 8 do not fit.