If 45 mL of water is added to 250 mL of a 0.75 M $K_{2} S O_{4}$ solution, what will be the molarity of the diluted solution?

0.75 M

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0.85 M

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0.64 M

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0.50 M

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Solution

The correct option is C 0.64 M
$M_{1} V_{1} = M_{2} V_{2} 0.75 \times 250 = M_{2} \times 295 M_{2} = \frac{(0.75 M) (250 m L)}{(295 m L)} = 0.636 M \sim 0.64 M$

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