If 5tan-4- then value of -5sin-4cos-5sin-4cos- is- -0-

The correct option is D 0 Divide both numerator and denominator by cos θ and solve (5 sin θ 4 cos θ)/(5 sin θ + 4 cos θ) = (5 sin θ 4 cos θ)/cos θ/(5 sin ...

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Standard IX

Mathematics

Trigonometric Ratios

If 5tanθ=4, t...

Question

If 5tan $θ$ =4, then value of (5sin $θ$ -4cos $θ$ )/(5sin $θ$ +4cos $θ$ ) is:

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Solution

The correct option is B
0

Divide both numerator and denominator by cos $θ$ and solve

$\frac{(5 s i n θ - 4 c o s θ)}{(5 s i n θ + 4 c o s θ)}$

= $\frac{\frac{(5 s i n θ - 4 c o s θ)}{c o s θ}}{\frac{(5 s i n θ + 4 c o s θ)}{c o s θ}}$

= $\frac{5 t a n θ - 4}{5 t a n θ + 4}$

= $\frac{4 - 4}{4 + 4}$ ( since, given that 5 tan $θ$ = 4 )

= 0

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If 5tan $θ$ =4, then value of (5sin $θ$ -4cos $θ$ )/(5sin $θ$ +4cos $θ$ ) is:

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If 5tanθ=4, then value of (5sinθ -4cosθ)/(5sinθ +4cosθ) is:

The correct option is B 0 Divide both numerator and denominator by cos θ and solve (5sinθ−4cosθ)(5sinθ+4cosθ) = (5sinθ−4cosθ)cosθ(5sinθ+4cosθ)cosθ = 5tanθ−45tanθ+4 = 4−44+4 ( since, given that 5 tan θ = 4 ) = 0

If 5tan $θ$ =4, then value of (5sin $θ$ -4cos $θ$ )/(5sin $θ$ +4cos $θ$ ) is: