If A - -a- b- c- B - -x- y- z- Find B - A None of these-a- x- -a- y- -a- z- -b- x- -b- y- -b- z- -c- x- -c- y- -c- z-x- a- -x- b- -x- c- -y- a- -y- b- -y- c- -z- a- -z- b- -z- c-a- a- -b- b- -c- c- -x- x- -y- y- -z- z-

The correct option is C (x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c) Multiplication of set B and set A B × A = (x, a), (x, b), (x, c ...

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Byju's Answer

Standard X

Mathematics

Finite and Infinite Sets

If A = (a, b,...

Question

If A = (a, b, c), B = (x, y, z). Find B $\times$ A

{(a, x), (a, y), (a, z), (b, x), (b, y), (b, z), (c, x), (c, y), (c, z)}

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{(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}

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{(a, a), (b, b), (c, c), (x, x), (y, y), (z, z)}

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None of these

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Solution

The correct option is B
{(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}

Multiplication of set B and set A

B $\times$ A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}

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Similar questions

If B $\times$ A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)} Find set A and set B.

Q. If

\frac{y}{b + c - a} = \frac{z}{c + a - b} = \frac{x}{a + b - c}

and

x + y + z \neq 0

, then which of the following hold true?

If B $\times$ A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}. Find set A and set B.

B $\times$ A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}. Find set A and set B.

Q. If a(y + z) = b(z + x) = c(x + y), then show that

\frac{y - z}{a (b - c)} = \frac{z - x}{b (c - a)} = \frac{x - y}{c (a - b)} .

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If A = (a, b, c), B = (x, y, z). Find B × A

The correct option is B {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)} Multiplication of set B and set A B × A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}

If A = (a, b, c), B = (x, y, z). Find B $\times$ A

The correct option is B
{(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}

Multiplication of set B and set A

B $\times$ A = {(x, a), (x, b), (x, c), (y, a), (y, b), (y, c), (z, a), (z, b), (z, c)}