If a ball is thrown up with a certain velocity- It attains a height of 40 m and comes back to the thrower- thenTotal distance covered by it is 40 mTotal displacement covered by it is 80 mTotal displacement is zeroTotal distance covered by it is zero-

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Distance and Displacement

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Question

If a ball is thrown up with a certain velocity. It attains a height of 40 m and comes back to the thrower, then

Total distance covered by it is 40 m

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Total displacement covered by it is 80 m

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Total displacement is zero

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Total distance covered by it is zero.

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Solution

The correct option is C Total displacement is zero
The ball thrown for height of 40m and comes back.
Hence $d i s t a n c e = 40 (u p) + 40 (d o w n) = 80 m$
$d i s p l a c e m e n t = 40 (u p) - 40 (d o w n) = 0 m$

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If a ball is thrown up with a certain velocity. It attains a height of 40 m and comes back to the thrower, then

The correct option is C Total displacement is zeroThe ball thrown for height of 40m and comes back. Hence distance=40(up)+40(down)=80mdisplacement=40(up)−40(down)=0m

The correct option is C Total displacement is zero
The ball thrown for height of 40m and comes back.
Hence $d i s t a n c e = 40 (u p) + 40 (d o w n) = 80 m$
$d i s p l a c e m e n t = 40 (u p) - 40 (d o w n) = 0 m$