If a ball is thrown vertically upwards with $40 m / s$ its velocity after two seconds will be:-

Open in App

Solution

Step 1: List the given values,
Initial velocity of the ball $u = 40 m / s$
Time period $t = 2 s$
It is acted upon by acceleration due to gravity $g$ in the downward, which is the opposite direction of motion of ball,
$∴ a = - g$
Where $g = 10 m / s^{2}$
Step 2: Calculate final velocity,
We know that the final velocity from the first equation of motion is given as,
$v = u + a t$
Upon substituting the values we get,
$v = 40 + (- 10) 2$
$= 40 - 20$
$= 20 m / s$
Hence, the final velocity of the ball after two seconds will be $20 m / s$ will be in the upwards direction.

Suggest Corrections

Similar questions

Q. If a ball is thrown vertically upwards with 40 m/s its velocity after two second will be:-

If a ball is thrown vertically upwards with a velocity of 40 $\frac{m}{s}$ , assuming $(g = 10 \frac{m}{s^{2}})$ then what will be the velocity of the ball after two seconds?

A stone is thrown vertically upwards with a velocity of 40 m/s. At what height will its kinetic energy and potential energy be equal?

Q. With what velocity should a ball be thrown vertically upward with so that it reaches a height of

40 m

A ball is thrown vertically down from the very high tower with velocity of 5 M per second with what velocity should another ball be thrown down after 2 seconds so that it can hit the first ball in 2 seconds?

Explain me this via relative as well without relative.

Answers is 40m/s

Join BYJU'S Learning Program

If a ball is thrown vertically upwards with 40m/s its velocity after two seconds will be:-

If a ball is thrown vertically upwards with $40 m / s$ its velocity after two seconds will be:-