If a body covers first half of its journey with uniform speed V1 and the second half of the journey with uniform speed V2 then the average speed is

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Solution

we know time=distance/speed

First half, time is d/V1

second half, time is d/V2

total time is (d/V1) + (d/V2) = d((1/V1) + (1/V2)) = d((V1+V2) / (V1.V2))

total time = d((V1+V2) / (V1.V2))

total distance = 2d

Average velocity = 2d/ d((V1+V2) / (V1.V2))
= 2 V1.V2 / (V1+V2)

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If a body covers first half of its journey with uniform speed V1 and the second half of the journey with uniform speed V2 then the average speed is

we know time=distance/speed First half, time is d/V1 second half, time is d/V2 total time is (d/V1) + (d/V2) = d((1/V1) + (1/V2)) = d((V1+V2) / (V1.V2)) total time = d((V1+V2) / (V1.V2)) total distance = 2d Average velocity = 2d/ d((V1+V2) / (V1.V2)) = 2 V1.V2 / (V1+V2) Like if satisfied

we know time=distance/speed

First half, time is d/V1

second half, time is d/V2

total time is (d/V1) + (d/V2) = d((1/V1) + (1/V2)) = d((V1+V2) / (V1.V2))

total time = d((V1+V2) / (V1.V2))

total distance = 2d

Average velocity = 2d/ d((V1+V2) / (V1.V2))
= 2 V1.V2 / (V1+V2)

Like if satisfied