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Question

If α and β are real then α+iββ+iα=

A
Lies betwen 0 and 1
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B
= 1
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C
>1
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D
2
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Solution

The correct option is B = 1
We know that
|z1z2| =|z1||z2|
Hence
|α+iββ+iα|
=|α+iβ||β+iα|
=α2+β2β2+α2
=1.

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