If an alkane has number of carbon atoms equal to n, then the number of moles of oxygen required for its complete combustion is?

\frac{3 n + 1}{2}

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2 n

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\frac{n}{2}

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(2 n + 1)

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Solution

The correct option is A $\frac{3 n + 1}{2}$
CH $_{4}$ +2O $_{2}$ $\to$ CO $_{2}$ +2H $_{2}$ O
C $_{2} H_{6}$ + $\frac{7}{2} O_{2}$ $\to$ 2CO $_{2}$ +3H $_{2}$ O
On observing these two reactions we can make general formula for requirement of oxygen molecules.
In general for an alkalane having 'n' number of carbon atoms
no. of moles of oxygen required will be= $\frac{3 n + 1}{2}$

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Similar questions

The homologous series of alcohols constitute compounds like CH₃OH, CH₂CH₂OH, together (CH₃CH₂CH₂OH) and so on. What is the number of moles of oxygen required to combust an alcohol of the same series having 'n' carbons ?

a) 3n + 1/2

b) 3n - 1/2

c) 2n + 1/2

d) 2n/3

Q. Number of moles of oxygen required for the combustion of one mole of an alkane is equal to:

A gaseous alkane is burnt completely in oxygen. The volume of $O_{2}$ required for complete combustion to the volume of $C O_{2}$ formed is 7:4. Determine the formula for alkane. [Alkane is $C_{n} H_{2 n + 2}$ ]

a gaseous alkane is exploded with oxygen. the moles of oxygen for complete combustion and carbon dioxide is in the ratio 7:4. deduce molecular formula of the alkane

5 L

of an alkane requires

25 L

of oxygen for its complete combustion. If all volumes are measured at constant temperature and pressure, then the alkane is:

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If an alkane has number of carbon atoms equal to n, then the number of moles of oxygen required for its complete combustion is?

The correct option is A 3n+12CH4 +2O2 → CO2 +2H2OC2H6+ 72O2 → 2CO2 +3H2OOn observing these two reactions we can make general formula for requirement of oxygen molecules.In general for an alkalane having 'n' number of carbon atoms no. of moles of oxygen required will be= 3n+12