If an alpha particle and a proton are accelerated from rest by a potential difference of 1 megavolt, then the ratio of their kinetic energy will b

Q. Three particles $\alpha$-particle, proton and deuteron are accelerated by the same potential difference. What is the ratio of kinetic energy :

Q. A proton, a deuteron and an $\alpha$ particle are accelerated through same potential difference and then they enter in a normal uniform magnetic field, the ratio of their kinetic energies will be:

Q. An $\alpha$ -particle has initial kinetic energy of 25 eV and it is accelerated through the potential difference of 150 volt. If a proton has initial kinetic energy of 25 eV and it is accelerated through the potential difference of 25 volt then find the approximate ratio of the final wavelengths associated with the proton and the $\alpha$ particle.

Q. A proton, a deuteron and an $\alpha$-particle is accelerated through the same potential difference from rest, enters a region of uniform magnetic field, moving at right angles to it. What is the ratio of their kinetic energies?

Q. An $\alpha$ - particle and a proton are accelerated from rest by a potential difference of $200\text{V}$. After this, their de Broglie wavelengths are ${\lambda }_{\alpha }$ and ${\lambda }_p$ respectively. The ratio $\frac{{\lambda }_p}{{\lambda }_{\alpha }}$ is :