If $\angle APB={60}^{\circ }$ and with B as the centre and any radius more than half of AB, another arc is drawn as shown. Taking A as the centre and the same radius as above, cut the previously drawn arc in Y and PY is drawn.

What will be the value of $\angle BPY$?

If $\angle APB={60}^{\circ }$ and with B as the centre and any radius more than half of AB, another arc is drawn as shown. Taking A as the centre and the same radius as above, cut the previously drawn arc in Y and PY is drawn.

What will be the value of $\angle BPY$?

Continuing with the previous question, what angle do we have at the end of four arcs?

With B as the centre and any radius more than half of AB, draw another arc as shown. This is the third arc. With A as the centre and the same radius as above, cut the previously drawn arc in Y. This would the fourth arc. Join PY.

What is ∠YPA?

Continuing with the previous question, what angle do we have at the end of four arcs?

With B as the centre and any radius more than half of AB, draw another arc as shown. This is the third arc. With A as the centre and the same radius as above, cut the previously drawn arc in Y. This would be the fourth arc. Join PY.

What is the angle ∠ YPA?

Continuing with the previous question, what angle do we have at the end of four arcs?

With B as the centre and any radius more than half of AB, draw another arc as shown. This is the third arc. With A as the centre and the same radius as above, cut the previously drawn arc in Y. This would the fourth arc. Join PY.

What is the angle $\angle YPA$?

Continuing with the previous question, what angle do we have at the end of four arcs?

With B as the centre and any radius more than half of AB, draw another arc as shown. This is the third arc. With A as the centre and the same radius as above, cut the previously drawn arc in Y. This would the fourth arc. Join PY.

What is the angle $\angle$YPA?