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Question

If cosx=|sinx|, then the general solution is

A
x=nπ+(1)nπ4, nZ
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B
x=nπ±π4, nZ
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C
x=(2n1)π±π4, nZ
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D
x=2nπ±π4, nZ
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Solution

The correct option is B x=nπ±π4, nZ
cosx=|sinx|
cos2x=sin2x
1sin2x=sin2x
2sin2x=1sinx=±12
x=nπ±π4, nZ

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