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Question

If f(x)=sin[π2]x+sin[π]2x, where [x] denotes teh greatest integer less than or equal to x, then,


A

f(π2)=1

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B

f(π)=2

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C

f(π4)=1

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D

None of these

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Solution

The correct option is A

f(π2)=1


f(x) sin [π2]x+sin [π]2 xf(x)=sin [9.8]x+sin [9.8]xf(x)=sin 9xsin 10xf(π2)=sin 9×π2sin 10×π2f(π2)=10=1


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