If $r_{1} = 9 c m$ and $r_{2} = 5 c m$ , then find the area of the shaded region. (Use $π = \frac{22}{7}$ )
176

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Solution

The correct option is A 176
Given,
Radius $r_{1} = 9 c m$
Radius $r_{2} = 5 c m$
$A r e a o f t h e c i r c l e = π r^{2} c m^{2}$

$A r e a o f t h e c i r c l e = π r_{1}^{2}$
$= π 9^{2} c m^{2}$
$= 81 π c m^{2}$

$A r e a o f t h e c i r c l e = π r_{2}^{2}$
$= π 5^{2} c m^{2}$
$= 25 π c m^{2}$

$A r e a o f t h e s h a d e d r e g i o n = 81 π c m^{2} - 25 π c m^{2} = 56 π c m^{2}$
$= \frac{22}{7} \times 56 c m^{2}$
$= 176 c m^{2}$

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If r1=9 cm and r2=5 cm, then find the area of the shaded region. (Use π=227)176

The correct option is A 176Given, Radius r1=9 cm Radius r2=5 cm Area of the circle=πr2 cm2 Area of the circle=πr21 =π 92 cm2 =81π cm2 Area of the circle=πr22 =π 52 cm2 =25π cm2 Area of the shaded region=81π cm2−25π cm2=56π cm2 =227×56 cm2 =176 cm2

If $r_{1} = 9 c m$ and $r_{2} = 5 c m$ , then find the area of the shaded region. (Use $π = \frac{22}{7}$ )
176