If $si{n}^{-1}\left(\frac{1}{3}\right)+si{n}^{-1}\left(\frac{2}{3}\right)=si{n}^{-1}x$, then x is equal to

The correct option is B $\frac{\sqrt{5}+4\sqrt{2}}{9}$
${\sin }^{-1}\frac{1}{3}+{\sin }^{-1}\frac{2}{3}{\sin }^{-1}\{\frac{1}{3}\sqrt{1-{\left(\frac{2}{3}\right)}^2}+\frac{2}{3}\sqrt{1-{\left(\frac{1}{3}\right)}^2}\}{\sin }^{-1}\{\frac{1}{3}\left(\frac{\sqrt{5}}{3}\right)+\frac{2}{3}\left(\frac{\sqrt{8}}{3}\right)\}{\sin }^{-1}\left\{\frac{\sqrt{5}+4\sqrt{2}}{9}\right\}x=\frac{\sqrt{5}+4\sqrt{2}}{9}$