If -i-l-2ncos-1x-i-0- then -i-l-2ncos-1x-i is 2nn-n-1-23nn

The correct option is A 2nSince, 0 ≤ cos^ 1x_i ≤π, ∴ cos^ 1x_i=0 for all i ∴ x_i=1 for all i ∴∑_i l^2ncos^ 1x_i=2n ...

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Standard XII

Mathematics

Area between x=g(y) and y Axis

If ∑_i-l^2nco...

Question

If $\sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 0$ , then $\sum_{i - l}^{2 n} c o s^{- 1} x_{i}$ is

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n(n+1)/2

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Solution

The correct option is B
2n

Since, $0 \leq c o s^{- 1} x_{i} \leq π, ∴ c o s^{- 1} x_{i} = 0$ for all i
$∴ x_{i} = 1$ for all i $∴ \sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 2 n$

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If $\sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 0$ , then $\sum_{i - l}^{2 n} c o s^{- 1} x_{i}$ is

The correct option is B
2n

Since, $0 \leq c o s^{- 1} x_{i} \leq π, ∴ c o s^{- 1} x_{i} = 0$ for all i
$∴ x_{i} = 1$ for all i $∴ \sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 2 n$

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If ∑2ni−lcos−1xi=0, then ∑2ni−lcos−1xi is

The correct option is B 2nSince, 0≤cos−1xi≤π,∴cos−1xi=0 for all i ∴xi=1 for all i ∴∑2ni−lcos−1xi=2n

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If $\sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 0$ , then $\sum_{i - l}^{2 n} c o s^{- 1} x_{i}$ is

The correct option is B
2n

Since, $0 \leq c o s^{- 1} x_{i} \leq π, ∴ c o s^{- 1} x_{i} = 0$ for all i
$∴ x_{i} = 1$ for all i $∴ \sum_{i - l}^{2 n} c o s^{- 1} x_{i} = 2 n$