If $\tan y=\sin x$ Find $\frac{dy}{dx}$

The correct option is A ${\cos }^{2}y\cos x$
$\tan x=\sin x\frac{d}{dx}\tan y=\frac{d}{dx}\sin x{\sec }^{2}y\frac{dy}{dx}=\cos x\frac{dy}{dx}={\cos }^{2}y\cos x$