If the angles $(2x-10{)}^o$ and $(x-5{)}^o$ are complementary angles, find $x$.

The correct option is A ${35}^o$

Angles $(2x-10{)}^o$ and $(x-5{)}^o$ are complementary.

According to the question, we have
$2x-10+x-5=90$
$\Rightarrow 3x-15=90$
$\Rightarrow x=\frac{105}{3}$
$\Rightarrow x=35$