If the applied torque is directly proportional to the angular displacement nbsp- nbsp- - then the work done in rotating the body through an angle nbsp- - would be -C is constant of proportionality-C - - 12-C- - 12- C - - -2-C - - -2-

The correct option is C 12 C θ ^2 We know, W=∫τ dθ τ=cθ W=∫ cθ dθ W=cθ^22 Option C is the correct answer ...

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SHM expression

If the applie...

Question

If the applied torque is directly proportional to the angular displacement $θ$ , then the work done in rotating the body through an angle $θ$ would be (C is constant of proportionality).

θ

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\frac{1}{2}

θ

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\frac{1}{2}

θ^{2}

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θ^{2}

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ω = (θ^{2} + θ),

θ = 1

θ

ω = θ^{2} + 2 θ

α

θ = 1 rad

\frac{tan θ}{(1 + {tan}^{2} θ)^{2}} + \frac{cot θ}{(1 + {cot}^{2} θ)^{2}} = sin θ \cdot cos θ

θ

{lim}_{θ \to - 1} f (θ)

\frac{θ^{2} + θ - 2}{θ + 3} \leq \frac{f (θ)}{θ^{2}} \leq \frac{θ^{2} + 2 θ - 1}{θ + 3}

θ = - 1

{lim}_{θ \to - 1} f (θ)

F

θ

s

F

θ

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