If the complement of an angle is ${27}^{\circ }$, then find its supplement.

Complement of an angle $={27}^o$

Let the angle be $x^o$

then, $x^o+{27}^o={90}^o$

$\therefore x^o={90}^o-{27}^o$

$\therefore x={63}^o$

Now, supplement of the angle

$={180}^o-x^o={180}^o-{63}^o$

$={117}^o$