If the first ionization energy of $He$ atom is $13.6eV$, then the second ionization energy of $He$ atom is :

Q. Ionization energy of $H{e}^{+}$ is 54.4 eV. The ionization energy of $L{i}^{2+}$ is:

Q. If the ionisation energy of hydrogen atom is $13.6eV$, what will be the ionisation energy of $H{e}^{+}$ and $L{i}^{2+}$ ions respectively?

Q. If the ionization energy for hydrogen atom is $13.6eV$, then the ionization energy for ${He}^{+}$ ion should be:

Q. The ionization potential of the hydrogen atom is 13.6 eV. Its energy in n = 2 energy state is

Q. The ionization energy of hydrogen is $13.6eV$. The first ionization energy of $He$ is $24.6eV$. Calculate the energy given out when $H{e}^{2+}$ nucleus combines with two electrons to form a helium atom in ground state.