If the mean of following frequency distribution. is $2.6$, then the value of f is:

$x_i$	1	2	3	4	5
$f_i$	5	4	f	2	3

The correct option is B $1$
Frequency Distribution table:

$xi$	$f_i$	$f_i{x}_i$
$1$	$5$	$5$
$2$	$4$	$8$
$3$	$f$	$3f$
$4$	$2$	$8$
$5$	$3$	$15$

$N=\Sigma f_i=14+f$

$\Sigma f_i{x}_i=36+3f$

Mean $=2.6=\frac{36+3f}{14+f}$

$\therefore 36.4+2.6f=36+3f$

$\therefore 0.4f=0.4$

$\therefore f=1$

Hence, option $B$ is correct.