If the radii of -160-the circular ends of a bucket are - 14- and - 6- m whose -160- height is - 6- m- What is the slant height of -160-the bucket - 10- 20- 30- 40-

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Question

If the radii of the circular ends of a bucket are $14$ and $6$ m whose height is $6$ m. What is the slant height of the bucket ?

10

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20

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30

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40

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Solution

The correct option is A $10$
Given: $R = 14 m, r = 6 m$ and $h = 6 m$
To find: Slant height, $l$
Solution: We know, $l = \sqrt{(R - r)^{2} + h^{2}}$
$= \sqrt{(14 - 6)^{2} + 6^{2}}$
$= \sqrt{8^{2} + 6^{2}}$
$= \sqrt{64 + 36}$
$= \sqrt{100}$
$= 10$
$∴$ Slant height $(l) = 10 m$
So, $A$ is the correct option.

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If the radii of the circular ends of a bucket are 14 and 6 m whose height is 6 m. What is the slant height of the bucket ?

The correct option is A 10Given: R=14 m,r=6 m and h=6 mTo find: Slant height, lSolution: We know, l=√(R−r)2+h2=√(14−6)2+62=√82+62=√64+36=√100=10∴ Slant height (l)=10 mSo, A is the correct option.

If the radii of the circular ends of a bucket are $14$ and $6$ m whose height is $6$ m. What is the slant height of the bucket ?