If the refractive indices of crown glass for red, yellow and violet colours are $1.5140$ , $1.5170$ and $1.6434$ , $1.6499$ and $1.6852$ respectively, then the dispersive power for crown and flint glass are respectively-

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Solution

For crown glass:
$ω = \frac{μ_{v} - μ_{r}}{μ_{y} - 1} = \frac{1.5318 - 1.5140}{1.5170 - 1} = 0.034$

For flint glass:
$ω = \frac{μ_{v} - μ_{r}}{μ_{y} - 1} = \frac{1.6852 - 1.6434}{1.6499 - 1} = 0.064$

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If the refractive indices of crown glass for red, yellow and violet colours are 1.5140. 1.5170 and 1.5318 respectively and for flint glass these are 1.6434, 1.6499 and 1.6852 respectively, then the dispersive power for crown and flint glass are respectively:

Q. If the refractive indices of crown glass for red, yellow and violet colours are 1.5140, 1.5170 and 1.5318 respectively and for flint glass these are 1.6434, 1.6499 and 1.6852 respectively, then the dispersive powers
for crown and flint glass are respectively

Q. If the refractive indices of crown glass for red, yellow and violet colours are respectively

μ_{r}, μ_{y}

and

μ_{v}

, then the dispersive power of this glass would be:

Q. If the refractive index of the crown glass for red, yellow and violet colours are

1.514, 1.517 and 1.531

respectively then, the dispersive power of the crown glass will be :

Q. If the refractive indices of a flint glass for red, yellow and violet colours are

1.42, 1.44 and 1.48

respectively then, the dispersive power of the glass is :

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If the refractive indices of crown glass for red, yellow and violet colours are 1.5140,1.5170 and 1.6434,1.6499 and 1.6852 respectively, then the dispersive power for crown and flint glass are respectively-

For crown glass:ω=μv−μrμy−1=1.5318−1.51401.5170−1=0.034 For flint glass:ω=μv−μrμy−1=1.6852−1.64341.6499−1=0.064

If the refractive indices of crown glass for red, yellow and violet colours are $1.5140$ , $1.5170$ and $1.6434$ , $1.6499$ and $1.6852$ respectively, then the dispersive power for crown and flint glass are respectively-

For crown glass:
$ω = \frac{μ_{v} - μ_{r}}{μ_{y} - 1} = \frac{1.5318 - 1.5140}{1.5170 - 1} = 0.034$

For flint glass:
$ω = \frac{μ_{v} - μ_{r}}{μ_{y} - 1} = \frac{1.6852 - 1.6434}{1.6499 - 1} = 0.064$