If the speed of light Is 3×108ms, Calculate the distance covered by light in 2.00ns.
Step 1: Given data
Speed of light v= 3×108ms
Time t = 2.00ns=2×10-9s
Step 2: Formula used
Distance covered S = speed of light v x timet
Step 3: Calculation
Hence, S=3×108×2×10-9=0.6m
Thus, distance covered will be 0.6m.
If the speed of light in glass is 2×108m/s, and that in air is 3×108ms, calculate the refractive index of glass with respect to air?
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