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Question

If the sum of LCM and HCF of two numbers is 260 and their LCM is 900 more than their HCF, then the product of two numbers is:

A
203400
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B
194400
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C
198400
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D
205400
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Solution

The correct option is B 194400
Let the HCF of the two numbers be x.
LCM = x + 900

Sum of LCM and HCF is 1260. (Given)
(x + 900) + x = 1260
2x + 900 = 1260
x + 450 = 630
x = 180

HCF = 180

LCM = 180 + 900 = 1080

Now, product of the two numbers = Product of their HCF and LCM
Product of the two numbers = 180 × 1080
Product of the two numbers = 194400

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