If time of flight of a projectile is 10 seconds and range is $500m$. Then what will be the maximum height attained by it?
Take $g=10m/s^2$.

Q. If time of flight of a projectile is 10 seconds. Range is 500 m. The maximum height attained by it will be

Q. If time of flight of a projectile is $10$ seconds. Range is $500m$. The maximum height attained by it will be:

Q. The time of flight of projectile is $10$ second and its range is $500m$. The maximum height reached by will be $(g=10m/s^2)$

Q. The speed of a projectile at its maximum height is $\frac{\sqrt{3}}{2}$ times its initial speed. If the range of the projectile is P times the maximum height attained by it, then P equals

Q. Consider the following statements $A$ and $B$ and mark the correct option.
$A)$ The maximum range is $4$ times the maximum height attained during its flight in the case of a projectile.
$B)$ In the case of a projectile the range $R$ is related to the time of flight $T$ as $R=5T^2$. If $g=10m{s}^{-2}$ the angle of projection is ${45}^o$.