If two cubes each of side 12 cm are joined end to end then the surface area of the resulting cuboid is

1728

c m^{2}

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1440

c m^{2}

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1445

c m^{2}

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1450

c m^{2}

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Solution

The correct option is B 1440 $c m^{2}$
Given the side of cube is 12 cm
Then if two cubes are joined Then the length of cuboid =12+12=24 cm, breadth is 12 cm and height is 12 cm
Then surface area of cuboid = $2 (24 \times 12 + \times 12 \times 12 + \times 24 \times 12) = 2 (288 + 144 + 288) = 2 \times 720 = 1440 c m^{2}$

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