If vectors P. Q and R have magnitude 5, 12 and 13 units $\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{R}$, the angle between Q and R is

Q.

If vectors P, Q and R have magnitude 5, 12 and 13 units and $\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{R}$, the angle between Q and R is

Q.

If vectors P, Q and R have magnitude 5, 12 and 13 units and $\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{R}$, the angle between Q and R is

Q. If vectors $P,Q$ and $R$ have magnitude $5,12$ and $13\text{units}$ and $\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{R}$, the angle between $Q$ and $R$ is ${\cos }^{-1}\frac{x}{y}$. Find $(y-x)$.

Q. If vectors $\overrightarrow{A},\overrightarrow{B}$ and $\overrightarrow{C}$ have magnitudes $5,12$ and $13$ units and $\overrightarrow{A}+\overrightarrow{B}=\overrightarrow{C},$ then the angle between $\overrightarrow{B}$ and $\overrightarrow{C}$ is

Q. Given that $P=12,Q=5$ and $R=13$ also $\overrightarrow{P}+\overrightarrow{Q}=\overrightarrow{R},$ then the angle between $\overrightarrow{P}$ and $\overrightarrow{Q}$ will be: