If z1,z2,z3 are the vertices of a triangle in argand plane such that |z1−z2|=|z1−z3|, then arg(2z1−z2−z3z3−z2) is
A
±π3
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B
0
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C
±π2
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D
±π6
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Solution
The correct option is C±π2 z1−z2z3−z2=|z1−z2||z3−z2|eiθ ⇒z1−z3z2−z3=|z1−z3||z2−z3|e−iθ ⇒z1−z2z3−z2+z1−z3z3−z2=Purely imaginary number So, arg(2z1−z2−z3z3−z2)=±π2