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Question

In a chess tournment, where the participants were to play one game with another. Two chess players fell ill, having played three games each. If the total number of games played is 84, the number of participants at the beginning was:

A
15
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B
16
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C
20
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D
21
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Solution

The correct option is A 15
Since 2 participants out of n fell ill, therefore the remaining players are n2

Since the 2 players had played 6 games, the remaining games will be = n2C2
n2C2+6=84
(n2)(n3)2+6=84
n25n150=0
n=15

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