In a conference hall, 2704 chairs are arranged in a way such that each row contains as many chairs as the number of rows. Find the number of rows and the number of chairs in each row.

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Solution

The correct option is D 52
It is mentioned that each row has as many chairs as the number of rows.

Let us find the factors of 2704.

$2704 = 2 \times 2 \times 2 \times 2 \times 13 \times 13$

Therefore, by dividing the factors equally into two parts, we get:
2704 = (2 × 2 × 13) × (2 × 2 × 13)

Hence, we can say that
Number of rows = Number of chairs
= 52

Hence, there are 52 rows, and each row has 52 chairs.

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