In a crystalline solid anions B are arranged in cubic close packing. Cation A are equally distributed between octahedral and tetrahedral voids.If all the octahedral voids are occupied, the formula for solid is

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A B_{2}

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A_{2} B

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A_{2} B_{3}

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Solution

The correct option is C $A_{2} B$
$B$ form $c c p$ .
let no. of $B$ is $n$ .
$\Rightarrow$ no of octahedral voids $= n$
no. of tetrahedral voids $= 2 n$
but cation $A$ is equally distributed in Oct. 8 tetr. voids as all Oct. voids are occupied $[i . e . n]$
$80$ cation $A$ is distributed as $n + n (O c t . + t e t r .)$
$\frac{B :}{A} = \frac{1 n}{2 n}$ $B : A :: 1 : 2$
Formula is $B A_{2}$ or $A_{2} B$

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