In a dihybrid Mendelian cross, garden pea plants heterozygous for yellow flowers and round seeds are crossed with homozygous white flowers and wrinkled seeds. The genotypic and phenotypic ratio of F1 progeny would be :

1. 3 : 1
2. 1 : 1 : 1 : 1
3. 1 : 2 : 2 : 1
4. 9 : 3 : 3 : 1

.A homozygous plant having round (R) and yellow (Y) seed is crossed with a homozygous plant having wrinkled(r) and green (y) seeds.:

Give the dihybrid phenotypic ratio and the phenotype of the offspring of the F₂ generation when two plants of the F1 generation are crossed.

A plant with purple flowers and wrinkled seeds were crossed with another white flower and round seeds. All the F1 progeny has purple flowers and round seeds.

Q. Name the dominant trait and genotype of the parents and the F1 progeny.

Let us assume in a given plant the genotype symbol "Y" stands for dominant yellow seed colour and "y" for recessive green seeds colour symbol "R" for round seed shape and "r" for wrinkled seeds. Two homozygous parents (plants) with genotypes "RRYY" and "rryy" are crossed and their F1 generation progeny is then selfed. What shall be the

a) Phenotype of F1 progeny

b) Genotype of F1 progeny

c) Gemete genotype of F1 progeny

d) Phenotypic ratio of F2 population

e) Phenotypic ratio of yellow seed to green and round seed to wrinkled seed in F2 population.