1
Question
In a double slit experiment if light of wavelength 5000 A∘ is used then fringe width of 1 mm is obtained. If now light of wavelength 6000 A∘ is used without altering the system then new fringe width will be :
- 1 mm
- 1.5 mm
- 0.5 mm
- 1.2 mm
- 1 mm
- 1.5 mm
- 0.5 mm
- 1.2 mm
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Solution
The correct option is D 1.2 mm
As fringe width is given by , β=λDd
1×10−3=(5000×10−10)×Dd
⇒Dd=(10−3)(5×10−7)
When the light of wavelength 6000A∘ is used then,
β=6000×10−10×(10−3)(5×10−7)
⇒β=1.2 mm
Hence, option (c) is the correct answer.
As fringe width is given by , β=λDd
1×10−3=(5000×10−10)×Dd
⇒Dd=(10−3)(5×10−7)
When the light of wavelength 6000A∘ is used then,
β=6000×10−10×(10−3)(5×10−7)
⇒β=1.2 mm
Hence, option (c) is the correct answer.
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