In a face-centred cubic lattice, atom A occupies the corner position and atom B occupies the face -centred positions. If one atom of B is missing from one of the face - centred points, the formula of the compound is

$A_{2} B_{5}$

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$A_{2} B$

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$A B_{2}$

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$A_{2} B_{2}$

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Solution

The correct option is A
$A_{2} B_{5}$

fcc Lattice, A $\to$ corner positions
B $\to$ Face- centres
$\Rightarrow$ One atom of B is missing from one of the face centres.
$A \Rightarrow \frac{1}{2} \times θ = 1 B \Rightarrow \frac{1}{2} \times 5 = \frac{5}{2} \Rightarrow A_{1} B_{\frac{5}{2}} \Rightarrow A_{2} B_{5}$

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In a face-centred cubic lattice, atom A occupies the corner position and atom B occupies the face -centred positions. If one atom of B is missing from one of the face - centred points, the formula of the compound is

The correct option is A A2B5 fcc Lattice, A → corner positions B → Face- centres ⇒ One atom of B is missing from one of the face centres. A⇒12×θ=1B⇒12×5=52⇒A1B52⇒A2B5