In a plate load test conducted on cohesionless soil, a 600 mm square test plate settles by 15 mm under a load intensity of $0.2 N / m m^{2} .$ All conditions remaining the same, settlement of a 1 m square footing will be

Less than 15mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Greater than 25mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15.60 mm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20.50mm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
20.50mm
$B_{1} = 600 m m$ $= 0.6 m$ Settlement $S_{1} = 15 m m$ $B_{2} = 1 m$ $\frac{S_{2}}{S_{1}} = {[\frac{B_{2} (B_{1} + 0.3)}{B_{1} (B_{2} + 0.3)}]}^{2}$ $\Rightarrow \frac{S_{2}}{15} = {[\frac{1 (0.6 + 0.3)}{0.6 (1 + 0.3)}]}^{2}$ $\Rightarrow S_{2} = 19.97 m m$

Suggest Corrections

Similar questions

Q. A plate load test is conducted on a cohesionless soil using a plate of size

0.6 m \times 0.6 m

. The settlement of the plate corresponding to ultimate load is 25 mm. What will be the settlement of footing of square shape having 3m dimension on the same soil at same load intensity?

Q. A plate load test is conducted on a cohesionless soil with a test plate having width

B_{p} (c m)

and settlement of this plate

S_{p} (c m)

is obtained at the same load intensity as a foundation. A footing having a width

B_{f} (c m)

is to be constructed as foundation. What is the settlement

S_{f} (c m)

experienced by this footing?

The permissible settlement of an isolated foundation on a granular soil is 40 mm. A plate load test is performed with 300 mm square plate undergoing a settlement of 20 mm under the same load intensity. The ultimate bearing capacity of soil with plate is $25 t / m^{2}$ . The ultimate bearing capacity of soil for foundation will be $t / m^{2}$

Q. A test plate 30 cm square, settles by 12 mm under a load of 4.5 kN in a sandy soil. By how much will a footing

2 m \times 2 m

subjected to a load of 200 kN settle?

Q. A test plate 30 cm

\times

30 cm resting on a sand deposit settles by 10 mm under a certain loading intensity. A footing 150 cm

\times

200 cm resting on the same sand deposit and loaded the same load intensity settles by

Join BYJU'S Learning Program

In a plate load test conducted on cohesionless soil, a 600 mm square test plate settles by 15 mm under a load intensity of 0.2N/mm2. All conditions remaining the same, settlement of a 1 m square footing will be

The correct option is D 20.50mmB1=600mm=0.6mSettlementS1=15mmB2=1mS2S1=[B2(B1+0.3)B1(B2+0.3)]2⇒S215=[1(0.6+0.3)0.6(1+0.3)]2⇒S2=19.97mm

In a plate load test conducted on cohesionless soil, a 600 mm square test plate settles by 15 mm under a load intensity of $0.2 N / m m^{2} .$ All conditions remaining the same, settlement of a 1 m square footing will be

The correct option is D
20.50mm
$B_{1} = 600 m m$ $= 0.6 m$ Settlement $S_{1} = 15 m m$ $B_{2} = 1 m$ $\frac{S_{2}}{S_{1}} = {[\frac{B_{2} (B_{1} + 0.3)}{B_{1} (B_{2} + 0.3)}]}^{2}$ $\Rightarrow \frac{S_{2}}{15} = {[\frac{1 (0.6 + 0.3)}{0.6 (1 + 0.3)}]}^{2}$ $\Rightarrow S_{2} = 19.97 m m$