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Question
In a population the frequency of a dominant allele is 0.6. What will be number of homozygous recessive individuals out of 400 individuals ?
In a population the frequency of a dominant allele is 0.6. What will be number of homozygous recessive individuals out of 400 individuals ?
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Solution
The correct option is D 64
The frequency of the dominant allele is denoted by 0.6 which is denoted by p. The frequency of the recessive allele is q.
So, p = 0.6
According to Hardy-Weinberg principle,
p+q=1
0.6+q=1
q=1−0.6
q=0.4
q2=.16
Homozygous recessive individuals =.16×400
=64
So, the correct answer is= 64
The frequency of the dominant allele is denoted by 0.6 which is denoted by p. The frequency of the recessive allele is q.
So, p = 0.6
According to Hardy-Weinberg principle,
p+q=1
0.6+q=1
q=1−0.6
q=0.4
q2=.16
Homozygous recessive individuals =.16×400
=64
So, the correct answer is= 64
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