In a population with two alleles for a gene locus (P and p), the allele frequency of P is 0.7. What would be the frequency of heterozygotes if the population is in Hardy-Weinberg equilibrium?

Q. A population is in Hardy- Weinberg equilibrium for a gene with only two alleles. If the gene frequency of an allele A is 0.7, the genotype frequency of Aa is:

Q. A population containing a gene 'X' with two alleles 'Aa' is in Hardy - Weinberg equilibrium for gene 'X'. If the gene frequency of allele 'A' is 0.2, allele frequency of 'a' is :

Q. In a certain population which is in Hardy Weinberg equilibrium, the frequency of allele A is 0.8 and that of allele a is 0.2. What would be the frequency of heterozygotes in this population at equilibrium?

Q. In a Hardy-Weinberg population, the frequency of allele A of gene A $a$ is 0.4. What is the frequency of allele $a$?

Q. Hardy-Weinberg equation helps in finding:
(I) Frequency of recessive allele responsible for X-linked recessive disease in a population
(II) Frequency of occurrence of alleles of a gene in a population
(III) Frequency of mutant gene in a population
(IV) Frequency of heterozygotes in a population

Choose the correct option.