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Question
In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now, another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is
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Solution
Given:
Wavelength of laser light:
λ=560×10−9 nm
Fringes' separation:
β1=7.2×10−3 mm
β2=8.1×10−3 mm
As we know that, fringe separation is directly proportional to wavelength of light so:
β1β2=λ1λ2
⇒ λ2=560×10−9×8.1×10−37.2×10−3
=6.3×10−7 m=630 nm
Given:
Wavelength of laser light:
λ=560×10−9 nm
Fringes' separation:
β1=7.2×10−3 mm
β2=8.1×10−3 mm
As we know that, fringe separation is directly proportional to wavelength of light so:
β1β2=λ1λ2
⇒ λ2=560×10−9×8.1×10−37.2×10−3
=6.3×10−7 m=630 nm
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