In an orthogonal machining operation, the tool life obtained is $10min$ at a cutting speed of $100m/min$ while at $75m/min$ cutting speed, the tool life is $30min$. The value of index $\left(n\right)$ in the Taylor's tool life equation is

Q. In a machining operation, doubling the cutting speed reduces the tool life to $1/8^{th}$ of the original value. The exponent $n$ in Taylor's tool life equation $V{T}^n=C$, is

Q. Linked Question:
In a machining experiment, tool life was found to vary with the cutting speed in the following manner:

Cutting speed $\left(m/min\right)$	Tool life $\left(minutes\right)$
$60$	$81$
$90$	$36$

The exponent $\left(n\right)$ and constant $\left(k\right)$ of the Taylor's tool life equation are

Q.

Taylor's tool life equation is given by $V{T}^n=C$ where V is in m/min and T is in min. In a turning operation, two tools X and Y are used. For tool X, n = 03 and C = 60 and for tool Y, n = 0.6 and C = 90. Both the tools will have the same tool life for the cutting speed (in m/min, round off to one decimal place) of

Q. Tool life of a $10$ hours is obtained when cutting with a single point tool at $63m/min$. If Taylor's constant $C=257.35,$ tool life on doubling the velocity will be

Q. For a certain job, the cost of metal cutting is Rs 18 C/V and the cost of tooling is Rs 270C(TV), where C is a constant, V is the cutting speed in m/min and T is the tool life in minutes. The Taylor's tool life equation is $V{T}^{0.25}=150$, The cutting speed (in m/min) for the minimum total cost is