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Work Energy Theorem Application

In figure sho...

Question

In figure shown below, the time taken by the projectile to reach from $A$ to $B$ is $t$ then, the distance $A B$ is equal to

\frac{u t}{\sqrt{3}}

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\frac{\sqrt{3} u t}{2}

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\sqrt{3} u t

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2 u t

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Solution

The correct option is B $\frac{u t}{\sqrt{3}}$
we have,

$A B = A C sec 30^{\circ}$

$= \frac{u}{2} t \times \frac{2}{\sqrt{3}}$

$= \frac{u t}{\sqrt{3}}$

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