In the figure shown, the coefficient of static friction between the blocks is $0.1,$ while the floor is frictionless. Find the minimum value of force $F$ (in $N$) to cause sliding between the blocks A and B of masses $5kg$ and $10kg$, respectively, when the angle of string is ${53}^{\circ }$ with horizontal. (Use $\sin {53}^{\circ }=4/5$ and $\cos {53}^{\circ }=3/5)$

Q. In the figure shown, the coefficient of static friction between $C$ and ground is $0.5$, coefficient of static friction between $A$ and $B$ is $0.25$, coefficient of static friction between $B$ and $C$ is zero. The minimum value of force $F$ (in Newton), to cause sliding between $A$ and $B$ is (Masses of $A,B$ and $C$ are respectively $2kg,4kg$ and $5kg$).

Q. In tha figure shown, the coefficeint of static friction between $C$ and ground is $0.5$, coefficeint of static friction between $A$ and $B$ is $0.25$, Coefficient of static friction between $B$ and $C$ is zero. Find the minimum value of force $F$, to cause sliding between $A$ and $B$. Masses of $A,B$ and $C$ are respectively $2kg,4kg$ and $5kg$.

Diagram

Q. Mass of block A is $100\text{kg}$ and that of block B is $200\text{kg}$. As shown in figure, the block A is attached to a string tied to the wall. The coefficient of static friction between blocks A and B is $({\mu }_s{)}_A=0.2$ and the coefficient of static friction between block B and floor is $({\mu }_s{)}_B=0.3$. Then calculate the minimum value of force $F$ required to move the block B. $(g=10{\text{m/s}}^2)$

Q. In figure, the coefficient of static friction between the floor and block $B$ is $0.30$. The coefficient of static friction between the block $B$ and $A$ is $0.15$. The mass of block $A$ is $\frac{m}{2}\text{kg}$ and $B$ is $m\text{kg}$. What is the maximum horizontal force $F$ in $\text{Newtons}$ that can be applied to block $B$, so that the two blocks move together?

Q. The figure shows a system of two blocks of $10kg$ and $5kg$ mass, connected by ideal strings and pulleys. Here the ground is smooth and the coefficient of friction between the two blocks is$\mu =0.5$. A horizontal force $F$ is applied on a lower block as shown. The minimum value of $F$ required to start sliding between the blocks is : (Take $g=10m/s^2)$