In the following compound, the number of sp hybridised carbons are:
$\begin{array}{ccccccc}C{H}_2=C=CH& -& CH& -& C& \equiv & CH\\ & & |& & & & \\ & & CN& & & & \end{array}$

Q. What is the hybridization state of carbon number $2$ and $3$ in the following compound $C{H}_2=CH-C\equiv CH$

Q. Which of the following molecules represents the order of hybridisation $s{p}^2$, $s{p}^2$, $sp$, $sp$ from left to right?

Q. In the compound $C{H}_3-CH=CH-C{H}_2-C\equiv CH$, the hybridisation of C₁, C₃ and C₅ bonds respectively is

Q.

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s{p}^3,s{p}^2,s{p}^2,s{p}^3,s{p}^2,s{p}^2,sp$ and $sp$. The structural formula of the hydrocarbon would be

Q. In the hydrocarbon $\underset{6}{{CH}_3}-\stackrel{{CH}_3}{\underset{{CH}_2}{C}-CH=\underset{3}{CH}}-\underset{2}{C}=\underset{1}{CH}$ the state of hybridisation of carbon $2,4$ and $5$ respectively are: