In the following numbers, replace * by the smallest number to make it divisible by $3$
$53 * 46$

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Solution

We know that,
For divisible by $3,$ the sum of the digits should be divisible by $3$
Sum of digits of $53 * 46 = 5 + 3 + * + 4 + 6 = 18$ , which is already divisible by $3$
So, * will be $0$
Hence, replace * by $0$ .

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Similar questions

In each of the following numbers, replace $*$ by the smallest number to make it divisible by $3$

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In each of the following numbers, replace M by the smallest number to make resulting number divisible by 3:

(i) 64 M 3

(ii) 46 M 46

(iii) 27 M 53

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