In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that $\theta$ is so small that $tan\theta \approx sin\theta$, then for equilibrium x is equal to

Q. Two similar balls of mass ‘m’ are hung by a silk thread of length L and carry similar charges Q as in figure Assuming the separation to be small, the separation between the balls (denoted by x) is equal to

Q. Two identical small equally charged conducting balls are suspended from long threads secured at one point. The charges and masses of the balls are such that they are in equilibrium when the distance between them is a (the length of thread L >> a). Then one of the balls is discharged. What will be the distance b(b << L) between the balls when equilibrium is restored?

Q. Two identical small equally charged conducting balls are suspended from long threads secured at one point. The charges and masses of the balls are such that they are in equilibrium when the distance between them is a (the length of the thread L >> a). One of the balls is then discharged. Again for the certain value of distance b (b << $l$) between the balls, the equilibrium is restored, the value of $\left(a^3/b^3\right)=?$

Q. Two similar conducting balls of mass m are hung from silk threads of length L and carry simillar charges q as shown in the figure. Assuming 0 to be small, the distance x between the ball is :

Q. Two identical tennis balls each having mass ${}^{\prime }{m}^{\prime }$ and charge ${}^{\prime }{q}^{\prime }$ are suspended from a fixed point by threads of length ${}^{\prime }{l}^{\prime }$. What is the equilibrium separation when each thread makes a small angle $\theta$ with the vertical ?