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Sulphuric Acid

In the reacti...

Question

In the reaction NaOH (hot and conc.) $+ C l_{2} \to N a C l + N a C l O_{3}$
Change in oxidation state of $C l_{2}$ is :

0

- 1

and

+ 5

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0

1

and

+ 3

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0

0

and

- 1

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0

1

and

+ 7

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Solution

The correct option is A $0$ to $- 1$ and $+ 5$
$\begin{matrix} O H^{-} & + & C l_{2} & \to & C l^{-} & + & C l O_{3}^{-} 0 & - 1 & + 5 \end{matrix}$

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