In the steady state circuit shown below, the cell is ideal, with emf $=2V$. The resistance of the coil of the galvanometer $G$ is $1\Omega$

The correct options are
B $0.2A$ current flows in $G$.
C Potential difference across $C_1$ is $1V$.
D Potential difference across $C_2$ is $1.2V$

As direct current doesnot flow through capacitor, current in the circuit can be considered as shown in figure.
From kirchhoffs law
$i=\frac{2}{4+1+5}=0.2$
Potential across $C_1=V_{AB}+V_{BC}=0.2\left(4\right)+0.2\left(1\right)=1\text{V}$
Potential across $C_2=V_{CD}+V_{BC}=0.2\left(5\right)+0.2\left(1\right)=1.2\text{V}$